---
title: Shrinking
tags:
  - Implementation
id: "589"
categories:
  - - OI
    - Common Skill
date: 2017-06-21 18:20:36
---

## 题目描述

Snuke can change a string $t$ of length $N$ into a string $t'$ of length $N-1$ under the following rule:

- for each $i \; (1 \le i \le N-1)$, the $i$-th character of $t'$ must be either the $i$-th or $(i+1)$-th character of $t$.

There is a string $s$ consisting of lowercase English letters. Snuke's objective is to apply the above operation to $s$ repeatedly so that all the characters in $s$ are the same. Find the minimum necessary number of operations.

## 题意概述

给定一个初始长度为$len$的字符串$s$。每次操作可以将$s$变成长度为$(len-1)$的字符串$s'$，并且满足

$$
\forall i \in [1, len-1], \; s_i'=s_i \lor s_i'=s_{i+1}
$$

问至少经过多少次操作使得$s$中所有字母都相同。

数据范围：$1 \le |s| \le 100$。

## 算法分析

事实上，我们只需要算出把$s$分别变成全是$a, b, c, ..., z$所需要的次数，取最小值即可。

如何求出这个次数呢？

假设$s$包含字母$i$，$i$把$s$分割成了至少$2$段。对于每一段来说，把这一段全部变成$i$所需要的次数就是这一段的长度。因此，把$s$全部变成$i$的次数就是每一段长度的最大值。

## 代码

```cpp
#include <iostream>
using namespace std;
string s;
int len, last[26], a[26], ans;
int main()
{
    cin >> s;
    len = ans = s.length();
    for (int i = 0; i < len; ++i) {
        a[s[i] - 'a'] = max(a[s[i] - 'a'], i - last[s[i] - 'a']);
        last[s[i] - 'a'] = i + 1;
    }
    for (int i = 0; i < 26; ++i) {
        ans = min(ans, max(a[i], len - last[i]));
    }
    cout << ans << endl;
    return 0;
}
```